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2.Motion in Straight Line
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The figure shows a velocity-time graph of a particle moving along a straight line If the particle starts from the position $x_0=-15\,m$ , then its position at $t=2\,s$ will be ........ $m$
A$-5$
B$5 $
C$10$
D$15 $
Solution
displacement $=$ Area convered by $v-t$ graph on time axis
$x-x_{0}=\frac{1}{2} \times 2 \times 10$
$x-(-15)=10 \Rightarrow x=-5 m$
$x-x_{0}=\frac{1}{2} \times 2 \times 10$
$x-(-15)=10 \Rightarrow x=-5 m$
Standard 11
Physics
